2x+y^2-3x^2+x-y^2-3x=

Solution for 2x+y^2-3x^2+x-y^2-3x= equation:

Simplifying
2x + y2 + -3x2 + x + -1y2 + -3x = 0

Reorder the terms:
2x + x + -3x + -3x2 + y2 + -1y2 = 0

Combine like terms: 2x + x = 3x
3x + -3x + -3x2 + y2 + -1y2 = 0

Combine like terms: 3x + -3x = 0
0 + -3x2 + y2 + -1y2 = 0
-3x2 + y2 + -1y2 = 0

Combine like terms: y2 + -1y2 = 0
-3x2 + 0 = 0
-3x2 = 0

Solving
-3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-3'.
x2 = 0

Simplifying
x2 = 0

Take the square root of each side:
x = {0}